Integrand size = 34, antiderivative size = 377 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=-\frac {B (b c-a d) g^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}+\frac {2 B (b c-a d)^2 g^4 (a+b x)^3 \left (2 A+B+2 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^2}-\frac {B (b c-a d)^3 g^4 (a+b x)^2 \left (6 A+7 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^3}+\frac {2 B (b c-a d)^4 g^4 (a+b x) \left (6 A+13 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^4}+\frac {2 B (b c-a d)^5 g^4 \left (6 A+25 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right ) \log \left (\frac {b c-a d}{b (c+d x)}\right )}{15 b d^5}+\frac {8 B^2 (b c-a d)^5 g^4 \operatorname {PolyLog}\left (2,\frac {d (a+b x)}{b (c+d x)}\right )}{5 b d^5} \]
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Time = 0.33 (sec) , antiderivative size = 377, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.147, Rules used = {2550, 2381, 2384, 2354, 2438} \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=\frac {2 B g^4 (b c-a d)^5 \log \left (\frac {b c-a d}{b (c+d x)}\right ) \left (6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+6 A+25 B\right )}{15 b d^5}+\frac {2 B g^4 (a+b x) (b c-a d)^4 \left (6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+6 A+13 B\right )}{15 b d^4}-\frac {B g^4 (a+b x)^2 (b c-a d)^3 \left (6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+6 A+7 B\right )}{15 b d^3}+\frac {2 B g^4 (a+b x)^3 (b c-a d)^2 \left (2 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+2 A+B\right )}{15 b d^2}-\frac {B g^4 (a+b x)^4 (b c-a d) \left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )+A\right )^2}{5 b}+\frac {8 B^2 g^4 (b c-a d)^5 \operatorname {PolyLog}\left (2,\frac {d (a+b x)}{b (c+d x)}\right )}{5 b d^5} \]
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Rule 2354
Rule 2381
Rule 2384
Rule 2438
Rule 2550
Rubi steps \begin{align*} \text {integral}& = \left ((b c-a d)^5 g^4\right ) \text {Subst}\left (\int \frac {x^4 \left (A+B \log \left (e x^2\right )\right )^2}{(b-d x)^6} \, dx,x,\frac {a+b x}{c+d x}\right ) \\ & = \frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}-\frac {\left (4 B (b c-a d)^5 g^4\right ) \text {Subst}\left (\int \frac {x^4 \left (A+B \log \left (e x^2\right )\right )}{(b-d x)^5} \, dx,x,\frac {a+b x}{c+d x}\right )}{5 b} \\ & = -\frac {B (b c-a d) g^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}+\frac {\left (B (b c-a d)^5 g^4\right ) \text {Subst}\left (\int \frac {x^3 \left (4 A+2 B+4 B \log \left (e x^2\right )\right )}{(b-d x)^4} \, dx,x,\frac {a+b x}{c+d x}\right )}{5 b d} \\ & = -\frac {B (b c-a d) g^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}+\frac {2 B (b c-a d)^2 g^4 (a+b x)^3 \left (2 A+B+2 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^2}-\frac {\left (B (b c-a d)^5 g^4\right ) \text {Subst}\left (\int \frac {x^2 \left (8 B+3 (4 A+2 B)+12 B \log \left (e x^2\right )\right )}{(b-d x)^3} \, dx,x,\frac {a+b x}{c+d x}\right )}{15 b d^2} \\ & = -\frac {B (b c-a d) g^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}+\frac {2 B (b c-a d)^2 g^4 (a+b x)^3 \left (2 A+B+2 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^2}-\frac {B (b c-a d)^3 g^4 (a+b x)^2 \left (6 A+7 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^3}+\frac {\left (B (b c-a d)^5 g^4\right ) \text {Subst}\left (\int \frac {x \left (24 B+2 (8 B+3 (4 A+2 B))+24 B \log \left (e x^2\right )\right )}{(b-d x)^2} \, dx,x,\frac {a+b x}{c+d x}\right )}{30 b d^3} \\ & = -\frac {B (b c-a d) g^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}+\frac {2 B (b c-a d)^2 g^4 (a+b x)^3 \left (2 A+B+2 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^2}-\frac {B (b c-a d)^3 g^4 (a+b x)^2 \left (6 A+7 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^3}+\frac {2 B (b c-a d)^4 g^4 (a+b x) \left (6 A+13 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^4}-\frac {\left (B (b c-a d)^5 g^4\right ) \text {Subst}\left (\int \frac {72 B+2 (8 B+3 (4 A+2 B))+24 B \log \left (e x^2\right )}{b-d x} \, dx,x,\frac {a+b x}{c+d x}\right )}{30 b d^4} \\ & = -\frac {B (b c-a d) g^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}+\frac {2 B (b c-a d)^2 g^4 (a+b x)^3 \left (2 A+B+2 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^2}-\frac {B (b c-a d)^3 g^4 (a+b x)^2 \left (6 A+7 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^3}+\frac {2 B (b c-a d)^4 g^4 (a+b x) \left (6 A+13 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^4}+\frac {2 B (b c-a d)^5 g^4 \left (6 A+25 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right ) \log \left (\frac {b c-a d}{b (c+d x)}\right )}{15 b d^5}-\frac {\left (8 B^2 (b c-a d)^5 g^4\right ) \text {Subst}\left (\int \frac {\log \left (1-\frac {d x}{b}\right )}{x} \, dx,x,\frac {a+b x}{c+d x}\right )}{5 b d^5} \\ & = -\frac {B (b c-a d) g^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{5 b d}+\frac {g^4 (a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2}{5 b}+\frac {2 B (b c-a d)^2 g^4 (a+b x)^3 \left (2 A+B+2 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^2}-\frac {B (b c-a d)^3 g^4 (a+b x)^2 \left (6 A+7 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^3}+\frac {2 B (b c-a d)^4 g^4 (a+b x) \left (6 A+13 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )}{15 b d^4}+\frac {2 B (b c-a d)^5 g^4 \left (6 A+25 B+6 B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right ) \log \left (\frac {b c-a d}{b (c+d x)}\right )}{15 b d^5}+\frac {8 B^2 (b c-a d)^5 g^4 \text {Li}_2\left (\frac {d (a+b x)}{b (c+d x)}\right )}{5 b d^5} \\ \end{align*}
Time = 0.32 (sec) , antiderivative size = 523, normalized size of antiderivative = 1.39 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=\frac {g^4 \left ((a+b x)^5 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2+\frac {B (b c-a d) \left (12 A b d (b c-a d)^3 x+12 B d (b c-a d)^3 (a+b x) \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )-6 d^2 (b c-a d)^2 (a+b x)^2 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )+4 d^3 (b c-a d) (a+b x)^3 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )-3 d^4 (a+b x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )-24 B (b c-a d)^4 \log (c+d x)-12 (b c-a d)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right ) \log (c+d x)+4 B (b c-a d)^2 \left (2 b d (b c-a d) x-d^2 (a+b x)^2-2 (b c-a d)^2 \log (c+d x)\right )+B (b c-a d) \left (6 b d (b c-a d)^2 x+3 d^2 (-b c+a d) (a+b x)^2+2 d^3 (a+b x)^3-6 (b c-a d)^3 \log (c+d x)\right )+12 B (b c-a d)^3 (b d x+(-b c+a d) \log (c+d x))+12 B (b c-a d)^4 \left (\left (2 \log \left (\frac {d (a+b x)}{-b c+a d}\right )-\log (c+d x)\right ) \log (c+d x)+2 \operatorname {PolyLog}\left (2,\frac {b (c+d x)}{b c-a d}\right )\right )\right )}{3 d^5}\right )}{5 b} \]
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\[\int \left (b g x +a g \right )^{4} {\left (A +B \ln \left (\frac {e \left (b x +a \right )^{2}}{\left (d x +c \right )^{2}}\right )\right )}^{2}d x\]
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\[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=\int { {\left (b g x + a g\right )}^{4} {\left (B \log \left (\frac {{\left (b x + a\right )}^{2} e}{{\left (d x + c\right )}^{2}}\right ) + A\right )}^{2} \,d x } \]
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Timed out. \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 2650 vs. \(2 (362) = 724\).
Time = 0.35 (sec) , antiderivative size = 2650, normalized size of antiderivative = 7.03 \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=\text {Too large to display} \]
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\[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=\int { {\left (b g x + a g\right )}^{4} {\left (B \log \left (\frac {{\left (b x + a\right )}^{2} e}{{\left (d x + c\right )}^{2}}\right ) + A\right )}^{2} \,d x } \]
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Timed out. \[ \int (a g+b g x)^4 \left (A+B \log \left (\frac {e (a+b x)^2}{(c+d x)^2}\right )\right )^2 \, dx=\int {\left (a\,g+b\,g\,x\right )}^4\,{\left (A+B\,\ln \left (\frac {e\,{\left (a+b\,x\right )}^2}{{\left (c+d\,x\right )}^2}\right )\right )}^2 \,d x \]
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